TI-92 -- Sequences -- Classifying 2-Cycles


You might want to look at the help screens below

for this module.

The screen below finds the equilibrium points for the model

r(p) = 0.5 + 0.0015 p - 0.000001166667 p (p - 500)
f(p) = r(p) p

p(n + 1) = f(p(n))

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The following screens show how the TI-92 can find 2-cycle points for this model.

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Notice that in the screens above we solve the equation

f(f(x)) = x

rather than the more natural equation

f(f(p)) = p

Of course, these two equations should be identical but for some reason the second one doesn't work on the TI-92. See the screen below.

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The next screen evaluates the derivative of the function f(f(x)) at the point 1353.9692 which is one of the 2-cycle points.

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Notice the derivative is less than one in absolute value, so this 2-cycle is attracting.

The next two screens look at an example with an initial population so high that the population drops below the "threshhold" and dies out.

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Copyright c 1995 by Frank Wattenberg, Department of Mathematics, Carroll College, Helena, MT 59625.