{VERSION 2 3 "APPLE_68K_MAC" "2.3" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 }{CSTYLE "" -1 256 "" 0 1 255 0 0 1 0 1 0 0 0 0 0 0 0 } {CSTYLE "" -1 257 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 258 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 259 "" 0 1 255 0 0 1 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 260 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{CSTYLE "" -1 261 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 256 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 256 "" 0 "" {TEXT -1 41 "Discrete and Continuous \+ Dynamical Systems" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 129 "The cell below shows how Maple can be used to work with \+ the discrete dynamical system used as an example in the browser window . " }{TEXT 256 15 "Evaluate it now" }{TEXT -1 1 "." }}{PARA 0 "" 0 " " {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 402 "k := 0.0 002:\nInitialValue := 0.50:\nDemand := p -> 1000 - 500 * p:\nSupply := p -> 1000 * p - 400:\nfcn := p -> p + k * (Demand(p) - Supply(p)):\n \nprice :=\n proc(n)\n if n = 1 then InitialValue else fcn(pric e(n-1))\n fi\n end:\n\nfor n from 1 to 20 \n do printf(`%4d \+ %10.4f`, n, price(n));\n print();\n od;\n\nplot([seq([n, price(n )], n = 1 .. 20)], \n year = 1 .. 20, title = `Prices`);" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 88 "Yo u can answer the questions about discrete dynamical systems by changin g the value of " }{TEXT 257 12 "InitialValue" }{TEXT -1 7 " and " } {TEXT 258 1 "k" }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }} {PARA 0 "" 0 "" {TEXT -1 135 "The cell below shows how Maple can be us ed to estimate the solution of initial value problems like the example in the browser window. " }{TEXT 259 15 "Evaluate it now" }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 223 "with(plots):\n\nk := 0.0002:\nInitialValue := 0.50: \n\ndiffeq := diff(p(t), t) = k*(Demand(p(t)) - Supply(p(t))):\n\nIVP \+ := \{diffeq, p(0) = InitialValue\}:\n\nsolution := dsolve(IVP, \{p(t) \}, numeric):\n\nodeplot(solution, p(t), 0..20);" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 119 "You can answer th e questions about initial value problems, or continuous dynamical syst ems, by changing the values of " }{TEXT 260 12 "InitialValue" }{TEXT -1 5 " and " }{TEXT 261 1 "k" }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}}{MARK "1 0 0" 13 }{VIEWOPTS 1 1 0 1 1 1803 }