Mathematical Structure
The Finite Dimensional Projection Theorem


Prerequisites:


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One of the most important tools we use for analyzing something is breaking it into parts. For example, if a force acts on a moving object we break the force into two components -- one component that is tangent to the motion of the object and another component that is perpendicular to the motion of the object. The tangential component causes the object to speed up or slow down and the perpendicular component causes it to turn.

In this module we develop a series of three very similar theorems that enable us to break a vector into parts.

Theorem

Suppose that x is a vector and that u is a unit vector. Let

Missing equation

Then

Missing equation

and

Missing equation

We call P the projection of x on u and R the residual. Notice that we have broken x into two pieces, one of which, P, is parallel to u and the other of which, R, is perpendicular to u.

Proof:

The first conclusion is obvious. For the second conclusion notice that

Missing equation


  1. Suppose that an object is moving in the direction given by the unit vector u = (3/5, 4/5) and that the force F = (1, 2) is acting on the object. Find the component of the force that is parallel to the motion of the object and the component of the force that is perpendicular to the object. answer.

  2. Break the vector x = (3, 5) up into two components one of which is parallel to the vector w = (1, 1) and the other of which is perpendicular to w. Warning: Notice that w is not a unit vector. answer.

  3. Suppose that x is a vectors and that w is a nonzero vector. Find a general formula for breaking x into two components one of which is parallel to w and the other of which is perpendicular to w. answer.

  4. Let C[-1, 1] denote the vector space of continuous functions on the interval [-1, 1] with the usual dot product. Decompose the function f(x) = x^3 into two pieces one of which is parallel to the function g(x) = x and the other of which is perpendicular to g(x). answer.

  5. Let C[-pi, pi] denote the vector space of continuous functions on the interval [-pi, pi] with the usual dot product. Decompose the function f(x) = 2 sin(x + 0.25) into two components one of which is a multiple of the function g(x) = sin x and the other of which is perpendicular to g(x). answer.


Theorem:

Suppose that x is a vector and that u and v are perpendicular unit vectors. Let

Missing equation

Then

Missing equation

and

Missing equation

and

Missing equation

We say that P is the component of x in the plane generated by u and v and that R is the residual or the component of x perpendicular to the plane generated by u and v.
This theorem is the mathematical tool that we use to

  1. Decompose the vector x = (1, 2, 3) into two components one of which is in the plane generated by the vectors

    u = (3/5, 4/5, 0) and v = (-4/5, 3/5, 0)

    and the other of which is perpendicular to this plane. answer .

  2. Decompose the vector x = (1, 2, 3) into two components one of which is in the plane generated by the vectors

    s = (1, 1, 0) and t = (-1, 1, 0)

    and the other of which is perpendicular to this plane. Warning: the two vectors s and t are perpendicular but they are not unit vectors. answer .

  3. Suppose that u and v are two vectors that are perpendicular but not necessarily unit vectors. Find a general formula for decomposing a vector x into two components one of which is in the plane generated by the vectors u and v and the other of which is perpendicular to this plane. answer .

  4. Let C[0, 1] denote the vector space of continuous functions on the interval [0, 1] with the usual dot product. Decompose the function

    f(x) = 3 sin(2 pi x + 0.15) + sin(4 pi x)

    into two components one of which is in the plane generated by the functions

    sin 2 pi x and cos 2 pi x

    and the other of which is perpendicular to this plane. answer .


Theorem:

Suppose that x is a vector and u1, u2, ... un are perpendicular unit vectors. Let

Missing equation

and

Missing equation

Then

Missing equation

and

Missing equation

Proof: The proof of this theorem is very similar to the proof of the previous theorem.

This theorem is the mathematical tool that we use to


Copyright c 1995 by Frank Wattenberg, Department of Mathematics, Montana State University, Bozeman, MT 59717