Mathematical Structure -- Vector Spaces
Magnitude or Length


Prerequisites:


This module follows a pattern that will become quite familiar. We begin by looking at a geometric idea in R2 where it is easy to draw pictures. Then we look at the same idea in R3 where the pictures are a little more difficult but we still have lots of geometric and physical experience. Then we move on to more exotic vector spaces where the geometry is no longer so evident but the algebraic machinery that we have developed still works. This allows us to use geometric ideas born in R2 and R3 to solve problems in more exotic settings.

If we think of a vector v = (x, y) in R2 as an arrow starting at the origin as shown in the figure below

Missing figure

then the Pythagorean Theorem tells us that the length of this arrow is

Missing equation

We use the notation ||v|| for the length or magnitude of a vector v.

Similarly, if we think of a vector v = (x, y, z) in R3 as an arrow starting at the origin as shown in the figure below

Missing figure

then once again the Pythagorean Theorem allows us to compute its length. First we consider the vector

L = (x, y, 0).

This vector is the hypotenuse of a right triangle whose three vertices are at the points

(0, 0, 0) , (x, 0, 0) , and (x, y, 0),

so its length is

Missing equation

Next consider the right triangle whose vertices are at the points

(0, 0, 0), (0, 0, z), and (x, y, z).

The vector (x, y, z) is the hypotenuse of this right triangle and its other two sides have length ||L|| and |z|, so its length is

Missing equation

We can generalize the formula above to vectors in Rn

Missing equation

We can use this formula to compute the distance between two points, represented by vectors u and v. The distance between two points is the length of the movement v - u required to move from one to the other -- that is,

The distance between u and v is ||v - u||.

This notion of length or magnitude has the following properties, called the magnitude properties.


  1. Find the length of the vector (3, 4). answer

  2. Find the length of the vector (3, 4, 5). answer

  3. Find the length of the vector (3, 4, 5, 6). answer

  4. Prove the first of the magnitude properties above --

    if v is a vector then ||v|| >= 0 and ||v|| = 0 if and only if v = O.

    answer

  5. Prove the second of the magnitude properties above --

    if c is a real number and v is a vector then ||c v|| = |c| ||v||.

    answer

    Note: We will not prove the triangle inequality here. It will be proved in the module on the dot product.

  6. Let C[a, b] denote the set of all continuous functions on the interval [a, b]. Define the usual two vector space operations on this set of functions. That is, if u and v are two functions in C[a, b] and c is a real number then the function u + v is given by

    (u + v)(t) = u(t) + v(t)

    and the function c u is given by

    (c u)(t) = c u(t).

    Define ||u|| by

    Missing equation

    Show that this notion of magnitude satisfies the first two magnitude properties. answer


Copyright c 1995 by Frank Wattenberg, Department of Mathematics, Montana State University, Bozeman, MT 59717