1. Yes. We must solve the equation

    
      t (-1, -1) + (1 - t) (5, 7) = (2, 3)
    (-t, -t) + (5 - 5 t, 7 - 7 t) = (2, 3)
               (5 - 6 t, 7 - 8 t) = (2, 3)
    

    which leads to the pair of equations

    
    5 - 6 t = 2
    7 - 8 t = 3
    

    Working with the first equation we see that

    
    5 - 6 t = 2
       -6 t = -3
          t = 1/2
    

    and with the second equation

    
    7 - 8 t = 3
       -8 t = -4
          t = 1/2.  
    

    Since these two equations have the same solution t = 1/2 the point (2, 3) is on the line determined by the two points (-1, -1) and (5, 7). Furthermore since t = 1/2 it is exactly halfway between these two points.

  2. No. We must solve the equation

    
      t (-1, -1) + (1 - t) (5, 7) = (3, 4)
    (-t, -t) + (5 - 5 t, 7 - 7 t) = (3, 4)
               (5 - 6 t, 7 - 8 t) = (3, 4)
    

    which leads to the pair of equations

    
    5 - 6 t = 3
    7 - 8 t = 4
    

    Working with the first equation we see that

    
    5 - 6 t = 3
       -6 t = -2
          t = 1/3
    

    and with the second equation

    
    7 - 8 t = 4
       -8 t = -3
          t = 3/8.  
    

    Since these two equations have different solutions the point (3, 4) is not on the line determined by the two points (-1, -1) and (5, 7).

  3. No.

  4. Yes.

  5. u + t v


Copyright c 1995 by Frank Wattenberg, Department of Mathematics, Montana State University, Bozeman, MT 59717