\documentclass[12pt]{article} \usepackage{amsmath,verbatim,graphpap} \def\ds {\displaystyle} \def\ra {\rightarrow} \textheight=9.5truein \textwidth=6.5truein \topmargin=-.5truein \oddsidemargin=0in \begin{document} {\large MATH 176 - Exam One \quad\quad\quad\quad Name:\underbar{\hskip 2.0truein}\\ \indent November 7, 2001 \quad\quad\quad\quad \quad Instructor:\underbar{\hskip 1.5truein} section: \underbar{\hskip .5truein}\\ \indent * * * SHOW YOUR WORK * * *\\ \hspace*{4.8in} \vspace*{-.75in} \begin{tabular}{|l|l|l|} \hline prob&points&score\\ \hline 1&30&\\ \hline 2&10&\\ \hline 3&30&\\ \hline 4&10&\\ \hline 5&10&\\ \hline 6&10&\\ \hline \hline Total&100&\\ \hline \end{tabular}} \vspace*{-1.5in} \begin{itemize} \item[ 1.] Find the derivative of the following functions \\ ({\bf DO NOT SIMPLIFY}): \begin{itemize} \item[a.] $\ds y = \rm{Arcsin}(x^3)$ \vspace{1.2in} \item[b.] $\ds y = \rm{Arctan}(\frac{2}{x})$ \vspace{1.2in} \item[c.] $\ds y = x^2 \ln( 2 x)$ \vspace{1.2in} \item[d.] $\ds y = (\ln (2x))^2$ \vspace{1.2in} \item[e.] $\ds y = xe^{-2x} $ \vspace{1.2in} \item[f.] $\ds y = \sec(e^{x+2})$ \end{itemize} \newpage \item[2.] Find the following integrals: \begin{itemize} \item[a.] $\ds \int \sin^{3}(x) \cos(x) ds$ \vspace{1.2in} \item[b.] $\ds \int (10+ e^{x})^{1/2} e^{x} dx $ \vspace{1.2in} \item[c.] $\ds \int \frac{1+e^{x}}{x+e^{x}} dx$ \vspace{1.2in} \item[d.] $\ds \int x^{4} e^{x^{5}} dx$ \vspace{1.2in} \item[e.] $\ds \int x^{2} \cos(x^{3}) dx$ \vspace{1.2in} \item[f.] $\ds \int \frac{ dx}{x^2 + 4 x + 8} $ \end{itemize} \newpage \item[3.] A force is given as a function of the distance from the origin by $F = \frac{\sin (x)}{2 + \cos(x)}$. Compute the work, $W$, done by this force as a function of $x$ if $W=0$ when $x=0$. \vspace{3in} \item[4.] Find the equation of the line normal to the graph of $y = x^2 \ln(x)$ at $(1,0)$. \vspace{3in} \item[5.] The vapor pressure $P$ over a liquid may be related to temperature by $\log P = (a/T) + b$. Solve for $P$. \vspace{3in} \item[6.] Find the volume generated by rotating the area bounded by $y=\sqrt{1-x^2}$, $x=0$, $y=0$ about the $y$-axis. \end{itemize} \end{document}