\section{(27 February 2009)}
\subsection*{Transport coefficients, cont.}

Recall:
\begin{align*}
     \mathcal{L} & = [H, \, \cdot \, ]  &  \rho & = \text{ equilibrium density 
matrix} &  &   \\
    \mathcal{L}_{\text{per}} & = \mathcal{L} + \vec{\lambda} \cdot 
    \vec{\delta} \, , & \vec{\delta} & = ( \delta_{1} , \ldots , 
    \delta_{n} ) \quad \text{commuting derivations:} &  [\delta_{i} , \delta_{j} ] & =0 \\
     &  & \vec{\lambda} & = (\lambda_{1} , \ldots , \lambda_{n} ) 
     \quad \text{complex constants} &  &
\end{align*}

Given the perturbation \( \vec{\lambda} \cdot 
    \vec{\delta} \) of \( \mathcal{L} \) there is a response: \( 
    \langle \vec{\delta} H \rangle_{\text{per}} = \tau ( 
    \rho_{\text{per}} \vec{\delta} H ) \), according to our 
    philosophy.
    
    Hypothesis:
    \begin{align*}
        \rho_{\text{per}} & = \text{``}\lim_{t\rightarrow\infty}\text{''} \mathrm{e}^{\mi t 
    \mathcal{L}_{\text{per}}} ( \rho )  \\
         & \hspace{2em} \uparrow \hspace{3em} \uparrow   \\
         & \hspace{2em} \uparrow \hspace{1em} \text{{\scriptsize equation of motion}} \\
         & \text{{\scriptsize very often must be regularized}}
    \end{align*}    
    Assumptions:
    \begin{itemize}
        \item[1)]   \( \tau \circ \delta = 0 \)
	
	Then
	\begin{align*}
	    \langle \vec{\delta} H \rangle_{\text{per}} & =
	    \tau ( \rho_{\text{per}} \vec{\delta} H ) = \lim_{t
	    \rightarrow \infty} \tau ( \mathrm{e}^{\mi t
	    \mathcal{L}_{\text{per}}} (\rho) \vec{\delta} \cdot
	    \vec{H} ) \\
	     & (\text{formally, } \, \tau(\mathcal{L}_{\text{per}}(\rho)A)
	     = -\tau(\rho \mathcal{L}_{\text{per}} (A))) \\
	     & = \lim_{t \rightarrow \infty} \tau(\rho
	     \mathrm{e}^{-\mi t \mathcal{L}_{\text{per}}}\vec{\delta}
	     \cdot \vec{H}) \tag{\( \ast \)}
	\end{align*}
    
	\item[2)] Bold assumption: use the Dyson expansion for \(
	\mathrm{e}^{-\mi t \mathcal{L}_{\text{per}}} \)
        \begin{align*}
            (\ast) & \overset{\text{Dyson}}{\underset{\text{power 
	    series in }\lambda}{=}} \tau ( \rho \, \vec{\delta} \cdot 
	    \vec{H} ) +  \underbrace{\lim_{t \rightarrow \infty}\tau 
	    \left( \rho \int_{\underset{ s_{0} + s_{1} \, 
	    = 1}{s_{0} , s_{1} \, \geq \, 0}} \mathrm{e}^{-\mi s_{0} 
	    \mathcal{L}} \vec{\lambda} \cdot \vec{\delta} 
	    \mathrm{e}^{-\mi s_{1} \mathcal{L}} \vec{\delta} \vec{H} \right)} + \bigoh ( \lambda^{2} )  \\
             & \hspace{8em} \rule[0em]{0.5pt}{2em} \hspace{12em} 
	     1^{\text{st}}\text{ order term}  \\
             & \hspace{5em} \lambda^{0}\text{-term; mostly} = 0  \\
             & \hspace{20em} \text{translate this thing}
        \end{align*}
    
        \item[3)]  \( 1^{\text{st}} \) order term.  Assumption: \( \bigoh 
	(\lambda^{2}) \) is really negligible.
	\[ 
	\langle \vec{\delta} H \rangle_{\text{per}} = \sigma^{\delta} 
	\vec{\lambda} \quad (\sigma^{\delta} \text{ is a matrix; a 
	tensor in the case of the higher order terms.})
	\]
	where
	\[ 
	\sigma^{\delta}_{\nu \mu} = \lim_{t \rightarrow \infty}
	    \overset{\sigma_{\nu \mu}(t)}{\overbrace{\tau 
	    \left( \rho \int_{0}^{t} \mathrm{e}^{-\mi (t - s_{1}) 
	    \mathcal{L}}  \delta_{\mu} 
	    \mathrm{e}^{-\mi s_{1} \mathcal{L}} \delta_{\nu} H 
	    \right) \mathrm{d} s_{1}}}
	\]
	is the tensor of transport coefficients in the \( 
	1^{\text{st}} \) order approximation (higher orders; higher 
	order tensors).  We have:
        \begin{align*}
	\sigma_{\nu \mu}(t) & = \tau \left( \underset{= \rho 
	\text{ by invariance}}{\underbrace{\mathrm{e}^{\mi (t - 
	s_{1})\mathcal{L}} (\rho)}} \delta_{\mu} \int_{0}^{t} 
	\mathrm{e}^{-s_{1}\mathcal{L}} \delta_{\nu} H \mathrm{d}s_{1} \right)  \\
	& \overset{\footnotemark}{=} \tau \left( -\delta_{\mu} (\rho) \int_{0}^{t} 
	\mathrm{e}^{-\mi s \mathcal{L}} \delta_{\nu} H \mathrm{d}s 
	\right)
        \end{align*}
	\footnotetext{Using the fact that \( \delta_{\mu} \) is a 
	derivation and that \( \tau \) is 
	invariant under \( \delta \).}
    \end{itemize}
    
     Now \emph{a priori} there is a singularity if \( t \rightarrow \infty 
    \) in case \( \delta_{\nu} \not\in \krn \mathcal{L}^{\perp} \).  
    Suppose that the temperature \( T \) is very low and the 
    Fermi energy \( E_{F} \in \mathrm{Gap}(H) \).  Hence \( \rho 
    =P_{F} = \) the spectral projection of \( H \) to states below 
    the Fermi energy:
    
\begin{figure*}[ht]
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% 	\put(2, 2.2){\line(0, 1){0.4}}
% 	\put(0.4, 0.8){\( \inf (H) \)}
% 	\put(6, 2.2){\line(0, 1){0.4}}
% 	\put(5.4, 0.8){\( E_{0}\)}
	\put(8, 1.8){\line(0, 1){0.4}}
	\put(7.4, 0.8){\( E_{F} \)}
	\put(7.6, 7){\( \rho = P_{F} \quad (T \rightarrow 0 )\)}
% 	\put(10, 2.2){\line(0, 1){0.4}}
% 	\put(9.4, 0.8){\( E_{1} \)}
% 	\put(-0.4, 7.75){\( 1 \cdots \)}
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% 	\put(-1, 2){\line(1,0){1}}
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	\qbezier(6, 8)(7, 8)(8, 5)
	\qbezier(8, 5)(9, 2)(10, 2)
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	\qbezier(8, 5)(10, 2)(12, 2)
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	\multiput(10, 1.8)(0.2, 0){11}{\line(0, 1){0.4}}
\end{picture}
\end{center}
\end{figure*}

\begin{remark*}
    If \( p = p^{2} \) and \( \delta \) is any derivation:
    \begin{align*}
        \delta (p^{2}) & = p \delta (p) + \delta (p) p \, , \text{ and}  \\
        || \, \, \, & \rule[0em]{0em}{0.1em} \\
        \delta (p) & = p \delta (p) + p^{\perp} \delta (p) \quad
	(p^{\perp} = 1 - p)  \\
        || \, \, \, & \rule[0em]{0em}{0.1em} \\
        \delta (p) & = \delta (p) p + \delta (p) p^{\perp} \quad
	(\text{ditto})  \\
        \Leftrightarrow \delta (p) p & = p^{\perp} \delta (p) \text{ 
	and } p \delta (p) = \delta (p) p^{\perp}  \\
	\text{put this together } \overset{\footnotemark}{\Rightarrow
	} \delta (p) & = p \delta (p) p^{\perp} + p^{\perp} \delta (p)
	p \tag{\( \ast \)}
    \end{align*}
\footnotetext{\( \delta (p) = p(p \delta (p)) + p^{\perp} (p^{\perp} 
\delta (p)) =  p \delta (p) p^{\perp} + p^{\perp} \delta (p) p\)}
\end{remark*}
\emph{The result marked \( (\ast) \) is an extremely important algebraic 
calculation.}

Suppose that we have an eigenbasis of \( H \) by \( \{ \psi_{i} 
\}_{i} \) (perhaps generalized eigenvectors).  Then
\begin{align*}
    \tau \left( \delta_{\mu} (P_{F}) \int_{0}^{t} 
    \mathrm{e}^{-\mi s \mathcal{L}} \delta_{\nu} H \mathrm{d}s 
    \right) & = \sum_{i,j} \underset{X_{ij}}{\underbrace{\langle \psi_{i} \, | \, \delta_{\mu} 
    P_{F} \, | \, \psi_{j} \rangle}} \langle \psi_{j} \, | \, \int_{0}^{t} \mathrm{e}^{-\mi 
    s \mathcal{L}}\delta_{\nu} H \, | \, \psi_{i} \rangle \\
    \text{where } X_{ij} & = 0 \text{ if both } \psi_{i} \text{ and } 
    \psi_{j} \text{ belong to either }  \\
    & \quad \im P_{F} \text{ or its 
    orthogonal complement}
\end{align*}

  \begin{quote}\emph{Notes are incomplete from here,}
      \[ \langle \psi_{j} \, | \, H \delta_{\nu} H 
        \, | \, \psi_{i} \rangle - \langle \psi_{j} \, | \,  \delta_{\nu} (H) H 
        \, | \, \psi_{i} \rangle \]
      
      \[ H | \psi_{i} \rangle = E_{i} | \psi_{i} \rangle \]
      
      \[ \Rightarrow |E_{i} - E_{j}| \geq |\tilde{E}_{1} - 
      \tilde{E}_{0}| \]
      \emph{to here}
  \end{quote}

So 
\[ 
\langle \psi_{j} | \int_{0}^{t} \mathrm{e}^{-\mi s \mathcal{L}} 
\delta_{\nu}|\psi_{i} \rangle \mathrm{d}s = \int_{0}^{t} 
\mathrm{e}^{-\mi s (E_{j} - E_{i})} \mathrm{d}s \, \langle \psi_{j} \, | \,  \delta_{\nu} H 
    \, | \, \psi_{i} \rangle
\]

\begin{align*}
\lim_{t \rightarrow \infty} \int_{0}^{t} \mathrm{e}^{-\mi s \omega} 
\mathrm{d}s & = \text{FT of the Heaviside function}  \\
& = \underset{\text{principal value}}{PV\left(\frac{1}{\mi \omega}\right)} + \frac{\pi}{2} 
\delta(\omega) \text{ in the distribution space}
\end{align*}

Hence 
\[ 
\frac{1}{\mi (E_{j} - E_{i})} \langle \psi_{j} \, | \,  \delta_{\nu} H 
    \, | \, \psi_{i} \rangle = \frac{1}{\mi} \langle \psi_{j} \, | 
    \,  \mathcal{L}^{-1} \delta_{\nu} H 
    \, | \, \psi_{i} \rangle
\]

Drawing everything together, 
\begin{proposition*}   
    \( \sigma^{\delta}_{\nu \mu} = \underset{\text{\textnormal{not at
    all invertible so need} } P_{F}}{\underset{\hspace{2.4em}
    |}{-\frac{1}{\mi}\tau \left( \delta_{\mu}(P_{F})
    \mathcal{L}^{-1} \delta_{\nu} H \right)}} \)
\end{proposition*}

Using the extremely important \( (\ast) \) twice (as well as commuting 
properties of \( \mathcal{L} \) with the projections), 
\begin{gather*}
    -\frac{1}{\mi}\tau \left( \delta_{\mu}(P_{F})
	\mathcal{L}^{-1} \delta_{\nu} H \right) = 
	-\frac{1}{\mi}\tau \left( P_{F} \delta_{\mu}(P_{F}) 
	P_{F}^{\perp}
	\mathcal{L}^{-1} \delta_{\nu} H + P_{F}^{\perp} 
	\delta_{\mu}(P_{F}) P_{F}
	\mathcal{L}^{-1} \delta_{\nu} H \right)  \\
      = -\frac{1}{\mi}\tau \left( P_{F} \delta_{\mu}(P_{F}) 
	P_{F}^{\perp}
	\mathcal{L}^{-1}( \delta_{\nu} (H) )P_{F} + P_{F}^{\perp} 
	\delta_{\mu}(P_{F}) P_{F}
	\mathcal{L}^{-1} (\delta_{\nu} (H) )P_{F}^{\perp} \right)  
\end{gather*}

\begin{lemma*}
    \begin{align*}
        P_{F}^{\perp} \mathcal{L}^{-1} (\delta_{\nu}(H)) P_{F} & =  
	-P_{F}^{\perp} \delta_{\nu}(P_{F}) P_{F} \\
        \text{\textnormal{and} }  P_{F} \mathcal{L}^{-1} (\delta_{\nu}(H)) P_{F}^{\perp} & =  
		P_{F} \delta_{\nu}(P_{F}) P_{F}^{\perp}
    \end{align*}
\end{lemma*}

\begin{proof}
    Apply \( \mathcal{L} \) to right-hand side:
    \begin{align*}
	\mathcal{L} \left( P_{F}^{\perp} \delta_{\nu} (P_{F}) P_{F}
	\right) & = P_{F}^{\perp} \!\!\!\!\!\!\!\! \underset{\delta_{\nu} 
	\underset{=0 - [ \delta_{\nu} (H), P_{F} ]}{[H, P_{F}] - [ \delta_{\nu} (H), P_{F} ]}}{\underbrace{[ H, \delta_{\nu}
	(P_{F}) ]}} \!\!\!\!\!\!\!\! P_{F} \, (\text{commutator in } H \text{ commutes with } (\delta_{\nu}
	H)) \\
         & = -P_{F}^{\perp} [ \delta_{\nu} (H), P_{F} ] P_{F}  \\
         & = -P_{F}^{\perp} \delta_{\nu} (H) P_{F}
    \end{align*}
    This proves the first equality.  The second is proved in the same 
    sort of way.
\end{proof}

Final result:
\begin{proposition*}
    \( \sigma^{\delta}_{\nu \mu} = -\mi \tau \left( P_{F} 
    \delta_{\mu} (P_{F}) \delta_{\nu} (P_{F}) - \delta_{\nu} (P_{F}) 
    \delta_{\mu} (P_{F}) \right) \)
\end{proposition*}
This is a non-commutative Chern character\,!!!
